(x^2-2x+6)+(5x^2-1/(x+3))=33

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Solution for (x^2-2x+6)+(5x^2-1/(x+3))=33 equation: 



(x^2-2x+6)+(5x^2-1/(x+3))=33

We move all terms to the left:

(x^2-2x+6)+(5x^2-1/(x+3))-(33)=0



Domain of the equation: (x+3))!=0

x∈R



We get rid of parentheses

x^2-2x+(5x^2-1/(x+3))+6-33=0

We multiply all the terms by the denominator


x^2*(x+3))-2x*(x+3))+(5x^2-1+6*(x+3))-33*(x+3))=0

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